3.536 \(\int \frac {(a+b \tanh ^{-1}(c x)) (d+e \log (f+g x^2))}{x^2} \, dx\)

Optimal. Leaf size=613 \[ -\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {1}{2} b c \log \left (\frac {g \left (1-c^2 x^2\right )}{c^2 f+g}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} b c e \text {Li}_2\left (\frac {c^2 \left (g x^2+f\right )}{f c^2+g}\right )+\frac {1}{2} b c \log \left (-\frac {g x^2}{f}\right ) \left (d+e \log \left (f+g x^2\right )\right )+\frac {1}{2} b c e \text {Li}_2\left (\frac {g x^2}{f}+1\right )-\frac {b e \sqrt {g} \text {Li}_2\left (-\frac {\sqrt {g} (1-c x)}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \text {Li}_2\left (\frac {\sqrt {g} (1-c x)}{\sqrt {-f} c+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \text {Li}_2\left (-\frac {\sqrt {g} (c x+1)}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \text {Li}_2\left (\frac {\sqrt {g} (c x+1)}{\sqrt {-f} c+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (c x+1) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \log (c x+1) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}} \]

[Out]

-(a+b*arctanh(c*x))*(d+e*ln(g*x^2+f))/x+1/2*b*c*ln(-g*x^2/f)*(d+e*ln(g*x^2+f))-1/2*b*c*ln(g*(-c^2*x^2+1)/(c^2*
f+g))*(d+e*ln(g*x^2+f))-1/2*b*c*e*polylog(2,c^2*(g*x^2+f)/(c^2*f+g))+1/2*b*c*e*polylog(2,1+g*x^2/f)-1/2*b*e*ln
(-c*x+1)*ln(c*((-f)^(1/2)-x*g^(1/2))/(c*(-f)^(1/2)-g^(1/2)))*g^(1/2)/(-f)^(1/2)+1/2*b*e*ln(c*x+1)*ln(c*((-f)^(
1/2)-x*g^(1/2))/(c*(-f)^(1/2)+g^(1/2)))*g^(1/2)/(-f)^(1/2)-1/2*b*e*ln(c*x+1)*ln(c*((-f)^(1/2)+x*g^(1/2))/(c*(-
f)^(1/2)-g^(1/2)))*g^(1/2)/(-f)^(1/2)+1/2*b*e*ln(-c*x+1)*ln(c*((-f)^(1/2)+x*g^(1/2))/(c*(-f)^(1/2)+g^(1/2)))*g
^(1/2)/(-f)^(1/2)-1/2*b*e*polylog(2,-(-c*x+1)*g^(1/2)/(c*(-f)^(1/2)-g^(1/2)))*g^(1/2)/(-f)^(1/2)-1/2*b*e*polyl
og(2,-(c*x+1)*g^(1/2)/(c*(-f)^(1/2)-g^(1/2)))*g^(1/2)/(-f)^(1/2)+1/2*b*e*polylog(2,(-c*x+1)*g^(1/2)/(c*(-f)^(1
/2)+g^(1/2)))*g^(1/2)/(-f)^(1/2)+1/2*b*e*polylog(2,(c*x+1)*g^(1/2)/(c*(-f)^(1/2)+g^(1/2)))*g^(1/2)/(-f)^(1/2)+
2*a*e*arctan(x*g^(1/2)/f^(1/2))*g^(1/2)/f^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.74, antiderivative size = 613, normalized size of antiderivative = 1.00, number of steps used = 28, number of rules used = 14, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.583, Rules used = {6081, 2475, 36, 29, 31, 2416, 2394, 2315, 2393, 2391, 5974, 205, 5972, 2409} \[ -\frac {1}{2} b c e \text {PolyLog}\left (2,\frac {c^2 \left (f+g x^2\right )}{c^2 f+g}\right )+\frac {1}{2} b c e \text {PolyLog}\left (2,\frac {g x^2}{f}+1\right )-\frac {b e \sqrt {g} \text {PolyLog}\left (2,-\frac {\sqrt {g} (1-c x)}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \text {PolyLog}\left (2,\frac {\sqrt {g} (1-c x)}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \text {PolyLog}\left (2,-\frac {\sqrt {g} (c x+1)}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \text {PolyLog}\left (2,\frac {\sqrt {g} (c x+1)}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {1}{2} b c \log \left (\frac {g \left (1-c^2 x^2\right )}{c^2 f+g}\right ) \left (d+e \log \left (f+g x^2\right )\right )+\frac {1}{2} b c \log \left (-\frac {g x^2}{f}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (c x+1) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \log (c x+1) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}} \]

Antiderivative was successfully verified.

[In]

Int[((a + b*ArcTanh[c*x])*(d + e*Log[f + g*x^2]))/x^2,x]

[Out]

(2*a*e*Sqrt[g]*ArcTan[(Sqrt[g]*x)/Sqrt[f]])/Sqrt[f] - (b*e*Sqrt[g]*Log[1 - c*x]*Log[(c*(Sqrt[-f] - Sqrt[g]*x))
/(c*Sqrt[-f] - Sqrt[g])])/(2*Sqrt[-f]) + (b*e*Sqrt[g]*Log[1 + c*x]*Log[(c*(Sqrt[-f] - Sqrt[g]*x))/(c*Sqrt[-f]
+ Sqrt[g])])/(2*Sqrt[-f]) - (b*e*Sqrt[g]*Log[1 + c*x]*Log[(c*(Sqrt[-f] + Sqrt[g]*x))/(c*Sqrt[-f] - Sqrt[g])])/
(2*Sqrt[-f]) + (b*e*Sqrt[g]*Log[1 - c*x]*Log[(c*(Sqrt[-f] + Sqrt[g]*x))/(c*Sqrt[-f] + Sqrt[g])])/(2*Sqrt[-f])
- ((a + b*ArcTanh[c*x])*(d + e*Log[f + g*x^2]))/x + (b*c*Log[-((g*x^2)/f)]*(d + e*Log[f + g*x^2]))/2 - (b*c*Lo
g[(g*(1 - c^2*x^2))/(c^2*f + g)]*(d + e*Log[f + g*x^2]))/2 - (b*e*Sqrt[g]*PolyLog[2, -((Sqrt[g]*(1 - c*x))/(c*
Sqrt[-f] - Sqrt[g]))])/(2*Sqrt[-f]) + (b*e*Sqrt[g]*PolyLog[2, (Sqrt[g]*(1 - c*x))/(c*Sqrt[-f] + Sqrt[g])])/(2*
Sqrt[-f]) - (b*e*Sqrt[g]*PolyLog[2, -((Sqrt[g]*(1 + c*x))/(c*Sqrt[-f] - Sqrt[g]))])/(2*Sqrt[-f]) + (b*e*Sqrt[g
]*PolyLog[2, (Sqrt[g]*(1 + c*x))/(c*Sqrt[-f] + Sqrt[g])])/(2*Sqrt[-f]) - (b*c*e*PolyLog[2, (c^2*(f + g*x^2))/(
c^2*f + g)])/2 + (b*c*e*PolyLog[2, 1 + (g*x^2)/f])/2

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 36

Int[1/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Dist[b/(b*c - a*d), Int[1/(a + b*x), x], x] -
Dist[d/(b*c - a*d), Int[1/(c + d*x), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0]

Rule 205

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(Rt[a/b, 2]*ArcTan[x/Rt[a/b, 2]])/a, x] /; FreeQ[{a, b}, x]
&& PosQ[a/b]

Rule 2315

Int[Log[(c_.)*(x_)]/((d_) + (e_.)*(x_)), x_Symbol] :> -Simp[PolyLog[2, 1 - c*x]/e, x] /; FreeQ[{c, d, e}, x] &
& EqQ[e + c*d, 0]

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2393

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Dist[1/g, Subst[Int[(a +
b*Log[1 + (c*e*x)/g])/x, x], x, f + g*x], x] /; FreeQ[{a, b, c, d, e, f, g}, x] && NeQ[e*f - d*g, 0] && EqQ[g
+ c*(e*f - d*g), 0]

Rule 2394

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))/((f_.) + (g_.)*(x_)), x_Symbol] :> Simp[(Log[(e*(f +
g*x))/(e*f - d*g)]*(a + b*Log[c*(d + e*x)^n]))/g, x] - Dist[(b*e*n)/g, Int[Log[(e*(f + g*x))/(e*f - d*g)]/(d +
e*x), x], x] /; FreeQ[{a, b, c, d, e, f, g, n}, x] && NeQ[e*f - d*g, 0]

Rule 2409

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((f_) + (g_.)*(x_)^(r_))^(q_.), x_Symbol] :> In
t[ExpandIntegrand[(a + b*Log[c*(d + e*x)^n])^p, (f + g*x^r)^q, x], x] /; FreeQ[{a, b, c, d, e, f, g, n, r}, x]
&& IGtQ[p, 0] && IntegerQ[q] && (GtQ[q, 0] || (IntegerQ[r] && NeQ[r, 1]))

Rule 2416

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.)*((h_.)*(x_))^(m_.)*((f_) + (g_.)*(x_)^(r_.))^(q
_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*Log[c*(d + e*x)^n])^p, (h*x)^m*(f + g*x^r)^q, x], x] /; FreeQ[{a,
b, c, d, e, f, g, h, m, n, p, q, r}, x] && IntegerQ[m] && IntegerQ[q]

Rule 2475

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.)*((f_) + (g_.)*(x_)^(s_))^(r_.),
x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(f + g*x^(s/n))^r*(a + b*Log[c*(d + e*x)^p])^q,
x], x, x^n], x] /; FreeQ[{a, b, c, d, e, f, g, m, n, p, q, r, s}, x] && IntegerQ[r] && IntegerQ[s/n] && Intege
rQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0])

Rule 5972

Int[ArcTanh[(c_.)*(x_)]/((d_.) + (e_.)*(x_)^2), x_Symbol] :> Dist[1/2, Int[Log[1 + c*x]/(d + e*x^2), x], x] -
Dist[1/2, Int[Log[1 - c*x]/(d + e*x^2), x], x] /; FreeQ[{c, d, e}, x]

Rule 5974

Int[(ArcTanh[(c_.)*(x_)]*(b_.) + (a_))/((d_.) + (e_.)*(x_)^2), x_Symbol] :> Dist[a, Int[1/(d + e*x^2), x], x]
+ Dist[b, Int[ArcTanh[c*x]/(d + e*x^2), x], x] /; FreeQ[{a, b, c, d, e}, x]

Rule 6081

Int[((a_.) + ArcTanh[(c_.)*(x_)]*(b_.))*((d_.) + Log[(f_.) + (g_.)*(x_)^2]*(e_.))*(x_)^(m_.), x_Symbol] :> Sim
p[(x^(m + 1)*(d + e*Log[f + g*x^2])*(a + b*ArcTanh[c*x]))/(m + 1), x] + (-Dist[(b*c)/(m + 1), Int[(x^(m + 1)*(
d + e*Log[f + g*x^2]))/(1 - c^2*x^2), x], x] - Dist[(2*e*g)/(m + 1), Int[(x^(m + 2)*(a + b*ArcTanh[c*x]))/(f +
g*x^2), x], x]) /; FreeQ[{a, b, c, d, e, f, g}, x] && ILtQ[m/2, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x^2} \, dx &=-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+(b c) \int \frac {d+e \log \left (f+g x^2\right )}{x \left (1-c^2 x^2\right )} \, dx+(2 e g) \int \frac {a+b \tanh ^{-1}(c x)}{f+g x^2} \, dx\\ &=-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} (b c) \operatorname {Subst}\left (\int \frac {d+e \log (f+g x)}{x \left (1-c^2 x\right )} \, dx,x,x^2\right )+(2 a e g) \int \frac {1}{f+g x^2} \, dx+(2 b e g) \int \frac {\tanh ^{-1}(c x)}{f+g x^2} \, dx\\ &=\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} (b c) \operatorname {Subst}\left (\int \left (\frac {d+e \log (f+g x)}{x}-\frac {c^2 (d+e \log (f+g x))}{-1+c^2 x}\right ) \, dx,x,x^2\right )-(b e g) \int \frac {\log (1-c x)}{f+g x^2} \, dx+(b e g) \int \frac {\log (1+c x)}{f+g x^2} \, dx\\ &=\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} (b c) \operatorname {Subst}\left (\int \frac {d+e \log (f+g x)}{x} \, dx,x,x^2\right )-\frac {1}{2} \left (b c^3\right ) \operatorname {Subst}\left (\int \frac {d+e \log (f+g x)}{-1+c^2 x} \, dx,x,x^2\right )-(b e g) \int \left (\frac {\sqrt {-f} \log (1-c x)}{2 f \left (\sqrt {-f}-\sqrt {g} x\right )}+\frac {\sqrt {-f} \log (1-c x)}{2 f \left (\sqrt {-f}+\sqrt {g} x\right )}\right ) \, dx+(b e g) \int \left (\frac {\sqrt {-f} \log (1+c x)}{2 f \left (\sqrt {-f}-\sqrt {g} x\right )}+\frac {\sqrt {-f} \log (1+c x)}{2 f \left (\sqrt {-f}+\sqrt {g} x\right )}\right ) \, dx\\ &=\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} b c \log \left (-\frac {g x^2}{f}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} b c \log \left (\frac {g \left (1-c^2 x^2\right )}{c^2 f+g}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} (b c e g) \operatorname {Subst}\left (\int \frac {\log \left (-\frac {g x}{f}\right )}{f+g x} \, dx,x,x^2\right )+\frac {1}{2} (b c e g) \operatorname {Subst}\left (\int \frac {\log \left (\frac {g \left (-1+c^2 x\right )}{-c^2 f-g}\right )}{f+g x} \, dx,x,x^2\right )+\frac {(b e g) \int \frac {\log (1-c x)}{\sqrt {-f}-\sqrt {g} x} \, dx}{2 \sqrt {-f}}+\frac {(b e g) \int \frac {\log (1-c x)}{\sqrt {-f}+\sqrt {g} x} \, dx}{2 \sqrt {-f}}-\frac {(b e g) \int \frac {\log (1+c x)}{\sqrt {-f}-\sqrt {g} x} \, dx}{2 \sqrt {-f}}-\frac {(b e g) \int \frac {\log (1+c x)}{\sqrt {-f}+\sqrt {g} x} \, dx}{2 \sqrt {-f}}\\ &=\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1+c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \log (1+c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} b c \log \left (-\frac {g x^2}{f}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} b c \log \left (\frac {g \left (1-c^2 x^2\right )}{c^2 f+g}\right ) \left (d+e \log \left (f+g x^2\right )\right )+\frac {1}{2} b c e \text {Li}_2\left (1+\frac {g x^2}{f}\right )+\frac {1}{2} (b c e) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {c^2 x}{-c^2 f-g}\right )}{x} \, dx,x,f+g x^2\right )-\frac {\left (b c e \sqrt {g}\right ) \int \frac {\log \left (-\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{-c \sqrt {-f}+\sqrt {g}}\right )}{1-c x} \, dx}{2 \sqrt {-f}}-\frac {\left (b c e \sqrt {g}\right ) \int \frac {\log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{1+c x} \, dx}{2 \sqrt {-f}}+\frac {\left (b c e \sqrt {g}\right ) \int \frac {\log \left (-\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{-c \sqrt {-f}-\sqrt {g}}\right )}{1-c x} \, dx}{2 \sqrt {-f}}+\frac {\left (b c e \sqrt {g}\right ) \int \frac {\log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{1+c x} \, dx}{2 \sqrt {-f}}\\ &=\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1+c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \log (1+c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} b c \log \left (-\frac {g x^2}{f}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} b c \log \left (\frac {g \left (1-c^2 x^2\right )}{c^2 f+g}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} b c e \text {Li}_2\left (\frac {c^2 \left (f+g x^2\right )}{c^2 f+g}\right )+\frac {1}{2} b c e \text {Li}_2\left (1+\frac {g x^2}{f}\right )-\frac {\left (b e \sqrt {g}\right ) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {\sqrt {g} x}{-c \sqrt {-f}-\sqrt {g}}\right )}{x} \, dx,x,1-c x\right )}{2 \sqrt {-f}}+\frac {\left (b e \sqrt {g}\right ) \operatorname {Subst}\left (\int \frac {\log \left (1+\frac {\sqrt {g} x}{c \sqrt {-f}-\sqrt {g}}\right )}{x} \, dx,x,1+c x\right )}{2 \sqrt {-f}}+\frac {\left (b e \sqrt {g}\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {\sqrt {g} x}{-c \sqrt {-f}+\sqrt {g}}\right )}{x} \, dx,x,1-c x\right )}{2 \sqrt {-f}}-\frac {\left (b e \sqrt {g}\right ) \operatorname {Subst}\left (\int \frac {\log \left (1-\frac {\sqrt {g} x}{c \sqrt {-f}+\sqrt {g}}\right )}{x} \, dx,x,1+c x\right )}{2 \sqrt {-f}}\\ &=\frac {2 a e \sqrt {g} \tan ^{-1}\left (\frac {\sqrt {g} x}{\sqrt {f}}\right )}{\sqrt {f}}-\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1+c x) \log \left (\frac {c \left (\sqrt {-f}-\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \log (1+c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \log (1-c x) \log \left (\frac {c \left (\sqrt {-f}+\sqrt {g} x\right )}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {\left (a+b \tanh ^{-1}(c x)\right ) \left (d+e \log \left (f+g x^2\right )\right )}{x}+\frac {1}{2} b c \log \left (-\frac {g x^2}{f}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {1}{2} b c \log \left (\frac {g \left (1-c^2 x^2\right )}{c^2 f+g}\right ) \left (d+e \log \left (f+g x^2\right )\right )-\frac {b e \sqrt {g} \text {Li}_2\left (-\frac {\sqrt {g} (1-c x)}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \text {Li}_2\left (\frac {\sqrt {g} (1-c x)}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {b e \sqrt {g} \text {Li}_2\left (-\frac {\sqrt {g} (1+c x)}{c \sqrt {-f}-\sqrt {g}}\right )}{2 \sqrt {-f}}+\frac {b e \sqrt {g} \text {Li}_2\left (\frac {\sqrt {g} (1+c x)}{c \sqrt {-f}+\sqrt {g}}\right )}{2 \sqrt {-f}}-\frac {1}{2} b c e \text {Li}_2\left (\frac {c^2 \left (f+g x^2\right )}{c^2 f+g}\right )+\frac {1}{2} b c e \text {Li}_2\left (1+\frac {g x^2}{f}\right )\\ \end {align*}

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Mathematica [C]  time = 3.27, size = 1226, normalized size = 2.00 \[ \text {result too large to display} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[((a + b*ArcTanh[c*x])*(d + e*Log[f + g*x^2]))/x^2,x]

[Out]

-((a*d)/x) - (b*d*ArcTanh[c*x])/x + b*c*d*Log[x] - (b*c*d*Log[1 - c^2*x^2])/2 + a*e*((2*Sqrt[g]*ArcTan[(Sqrt[g
]*x)/Sqrt[f]])/Sqrt[f] - Log[f + g*x^2]/x) + (b*e*(-(((2*ArcTanh[c*x] + c*x*(-2*Log[x] + Log[1 - c^2*x^2]))*Lo
g[f + g*x^2])/x) - 2*c*(Log[x]*(Log[1 - (I*Sqrt[g]*x)/Sqrt[f]] + Log[1 + (I*Sqrt[g]*x)/Sqrt[f]]) + PolyLog[2,
((-I)*Sqrt[g]*x)/Sqrt[f]] + PolyLog[2, (I*Sqrt[g]*x)/Sqrt[f]]) + c*(Log[-c^(-1) + x]*Log[(c*(Sqrt[f] - I*Sqrt[
g]*x))/(c*Sqrt[f] - I*Sqrt[g])] + Log[c^(-1) + x]*Log[(c*(Sqrt[f] - I*Sqrt[g]*x))/(c*Sqrt[f] + I*Sqrt[g])] + L
og[-c^(-1) + x]*Log[(c*(Sqrt[f] + I*Sqrt[g]*x))/(c*Sqrt[f] + I*Sqrt[g])] - (Log[-c^(-1) + x] + Log[c^(-1) + x]
- Log[1 - c^2*x^2])*Log[f + g*x^2] + Log[c^(-1) + x]*Log[1 - (Sqrt[g]*(1 + c*x))/(I*c*Sqrt[f] + Sqrt[g])] + P
olyLog[2, (c*Sqrt[g]*(c^(-1) + x))/(I*c*Sqrt[f] + Sqrt[g])] + PolyLog[2, (I*Sqrt[g]*(-1 + c*x))/(c*Sqrt[f] - I
*Sqrt[g])] + PolyLog[2, ((-I)*Sqrt[g]*(-1 + c*x))/(c*Sqrt[f] + I*Sqrt[g])] + PolyLog[2, (I*Sqrt[g]*(1 + c*x))/
(c*Sqrt[f] + I*Sqrt[g])]) + (c*g*((2*I)*ArcCos[(-(c^2*f) + g)/(c^2*f + g)]*ArcTan[(c*g*x)/Sqrt[c^2*f*g]] - 4*A
rcTan[(c*f)/(Sqrt[c^2*f*g]*x)]*ArcTanh[c*x] + (ArcCos[(-(c^2*f) + g)/(c^2*f + g)] + 2*ArcTan[(c*g*x)/Sqrt[c^2*
f*g]])*Log[((2*I)*c*f*(I*g + Sqrt[c^2*f*g])*(-1 + c*x))/((c^2*f + g)*(c*f + I*Sqrt[c^2*f*g]*x))] + (ArcCos[(-(
c^2*f) + g)/(c^2*f + g)] - 2*ArcTan[(c*g*x)/Sqrt[c^2*f*g]])*Log[(2*c*f*(g + I*Sqrt[c^2*f*g])*(1 + c*x))/((c^2*
f + g)*(c*f + I*Sqrt[c^2*f*g]*x))] - (ArcCos[(-(c^2*f) + g)/(c^2*f + g)] + 2*(ArcTan[(c*f)/(Sqrt[c^2*f*g]*x)]
+ ArcTan[(c*g*x)/Sqrt[c^2*f*g]]))*Log[(Sqrt[2]*Sqrt[c^2*f*g])/(E^ArcTanh[c*x]*Sqrt[c^2*f + g]*Sqrt[c^2*f - g +
(c^2*f + g)*Cosh[2*ArcTanh[c*x]]])] - (ArcCos[(-(c^2*f) + g)/(c^2*f + g)] - 2*(ArcTan[(c*f)/(Sqrt[c^2*f*g]*x)
] + ArcTan[(c*g*x)/Sqrt[c^2*f*g]]))*Log[(Sqrt[2]*E^ArcTanh[c*x]*Sqrt[c^2*f*g])/(Sqrt[c^2*f + g]*Sqrt[c^2*f - g
+ (c^2*f + g)*Cosh[2*ArcTanh[c*x]]])] + I*(PolyLog[2, ((-(c^2*f) + g - (2*I)*Sqrt[c^2*f*g])*(I*c*f + Sqrt[c^2
*f*g]*x))/((c^2*f + g)*((-I)*c*f + Sqrt[c^2*f*g]*x))] - PolyLog[2, ((-(c^2*f) + g + (2*I)*Sqrt[c^2*f*g])*(I*c*
f + Sqrt[c^2*f*g]*x))/((c^2*f + g)*((-I)*c*f + Sqrt[c^2*f*g]*x))])))/Sqrt[c^2*f*g]))/2

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fricas [F]  time = 0.77, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {b d \operatorname {artanh}\left (c x\right ) + a d + {\left (b e \operatorname {artanh}\left (c x\right ) + a e\right )} \log \left (g x^{2} + f\right )}{x^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arctanh(c*x))*(d+e*log(g*x^2+f))/x^2,x, algorithm="fricas")

[Out]

integral((b*d*arctanh(c*x) + a*d + (b*e*arctanh(c*x) + a*e)*log(g*x^2 + f))/x^2, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b \operatorname {artanh}\left (c x\right ) + a\right )} {\left (e \log \left (g x^{2} + f\right ) + d\right )}}{x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arctanh(c*x))*(d+e*log(g*x^2+f))/x^2,x, algorithm="giac")

[Out]

integrate((b*arctanh(c*x) + a)*(e*log(g*x^2 + f) + d)/x^2, x)

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maple [F]  time = 2.02, size = 0, normalized size = 0.00 \[ \int \frac {\left (a +b \arctanh \left (c x \right )\right ) \left (d +e \ln \left (g \,x^{2}+f \right )\right )}{x^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a+b*arctanh(c*x))*(d+e*ln(g*x^2+f))/x^2,x)

[Out]

int((a+b*arctanh(c*x))*(d+e*ln(g*x^2+f))/x^2,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{2} \, {\left (c {\left (\log \left (c^{2} x^{2} - 1\right ) - \log \left (x^{2}\right )\right )} + \frac {2 \, \operatorname {artanh}\left (c x\right )}{x}\right )} b d + {\left (\frac {2 \, g \arctan \left (\frac {g x}{\sqrt {f g}}\right )}{\sqrt {f g}} - \frac {\log \left (g x^{2} + f\right )}{x}\right )} a e + \frac {1}{2} \, b e \int \frac {{\left (\log \left (c x + 1\right ) - \log \left (-c x + 1\right )\right )} \log \left (g x^{2} + f\right )}{x^{2}}\,{d x} - \frac {a d}{x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*arctanh(c*x))*(d+e*log(g*x^2+f))/x^2,x, algorithm="maxima")

[Out]

-1/2*(c*(log(c^2*x^2 - 1) - log(x^2)) + 2*arctanh(c*x)/x)*b*d + (2*g*arctan(g*x/sqrt(f*g))/sqrt(f*g) - log(g*x
^2 + f)/x)*a*e + 1/2*b*e*integrate((log(c*x + 1) - log(-c*x + 1))*log(g*x^2 + f)/x^2, x) - a*d/x

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\left (a+b\,\mathrm {atanh}\left (c\,x\right )\right )\,\left (d+e\,\ln \left (g\,x^2+f\right )\right )}{x^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*atanh(c*x))*(d + e*log(f + g*x^2)))/x^2,x)

[Out]

int(((a + b*atanh(c*x))*(d + e*log(f + g*x^2)))/x^2, x)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a+b*atanh(c*x))*(d+e*ln(g*x**2+f))/x**2,x)

[Out]

Timed out

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